So, we know how derivatives work, which is fantastic. So far, we've only looked at one very simple example. From our previous work, we found that when it means
We'll take a quick look at another simple example, then we'll add them together, then work out a proof that works for all sums.
Our second example will be . So, we know that . Further, we know that this means that . Plugging in our value for which is amusingly just x, we can say with
certainty that
Simplifying, we are left with . At this point, it's safe to say that no longer has any influence on our function so the limit as approaches is simply .
We can now say that when it means
So, what happens when we combine the two? Let's say our new function is
We know that
A little bit of expansion and this becomes
Now we simplify and come up with
Then we clean up our denominator yielding:
Solve for our limit by plugging in 0, and we are left with
The astute among you will notice that as our original function was , the resulting derivative is equal to
We can prove that this is true for all sums with relative ease:
Given that we can see simply that the change in or is equal to
In terms we are familiar with , this means
Next we divide both sides by h giving us
Finally, we apply the limit as h approaches 0 to both sides
That form should look familiar. In fact we can see that
and
and
Which formalizes as
We now know that anytime we are provided with a function with sums (it works with subtraction too, just think about it) we can derive each piece of the sum individually.
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